Haber Process: cooling

Gap-fill exercise

Fill in all the gaps, then press "Check" to check your answers. Use the "Hint" button to get a free letter if an answer is giving you trouble. You can also click on the "[?]" button to get a clue. Note that you will lose points if you ask for hints or clues!
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Cooling a system that is in equilibrium has two effects. Firstly, by [de/in]creasing the kinetic energy of all the molecules, it [reduces/increases] the rates of both the forward and reverse reactions. Secondly, it has the effect of disturbing the by favouring the [exo/endo]thermic reaction until a new equilibrium is reached with [the same/a different] equilibrium constant.
If heat is removed from a system in the Haber Process, the [exo/endo]thermic [forward/reverse] reaction is favoured to [cool the system back down/heat the system back up]. For a while, the system will not be in as the [forward/reverse] reaction occurs more rapidly than the [forward/reverse] reaction. This will [in/de]crease the amount of ammonia present, and [in/de]crease the amount of hydrogen and nitrogen. After a while a new dynamic equilibrium is reached. The rates of forward and reverse reactions are again to one another, and the amounts of reactants and products will remain . However, compared to before the pressure was applied, there will now be [less/more] ammonia present at equilibrium. A new equilibrium constant, Kc, [higher than/lower than/the same as] that of the original equilibrium, is reached.